Program :
Output :
#include<stdio.h> #include<conio.h> #include<stdio.h> void bubble_sort(int [],int); void main() { int a[30],n,i; printf("\nEnter no of elements :"); scanf("%d",&n); printf("\nEnter array elements :"); for(i=0;i<n;i++) scanf("%d",&a[i]); bubble_sort(a,n); getch(); } //--------------------------------- Function void bubble_sort(int a[],int n) { int i,j,k,temp; printf("\nUnsorted Data:"); for(k=0;k<n;k++) printf("%5d",a[k]); for(i=1;i< n;i++) { for(j=0;j< n-1;j++) if(a[j]>a[j+1]) { temp=a[j]; a[j]=a[j+1]; a[j+1]=temp; } printf("\nAfter pass %d : ",i); for(k=0;k< n;k++) printf("%5d",a[k]); } }
What Happens After Each Iteration ?
- There are ‘N’ number of Unsorted Elements
- Total Number of Iterations = N-1
- At the End of First Iteration : Largest Element Will get its Exact Final Position
- At the End of 2nd Iteration : 2nd Largest Element Will get its Exact Final Position
- .
- .
- .
- .
- At the End of (N-1)th Iteration : (N-1)th Largest Element Will get its Exact Final Position
Output :
Enter no of elements :5 Enter array elements :10 4 55 21 6 Unsorted Data: 10 4 55 21 6 After pass 1 : 4 10 21 6 55 After pass 2 : 4 10 6 21 55 After pass 3 : 4 6 10 21 55 After pass 4 : 4 6 10 21 55
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